MCQ
The reaction, which forms nitric oxide, is
- A$C$ and ${N_2}O$
- B$Cu$ and ${N_2}O$
- C$Na$ and $N{H_3}$
- ✓$Cu$ and $HN{O_3}$
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(image) $\xrightarrow{{B{r_3} + C{H_3} - COOH}}A\xrightarrow{{Alc.KOH}}B$ (Product with six membered ring) $\xrightarrow[{(2)\,{H_2}O}]{{(1)\,C{H_3} - MgBr}}C\xrightarrow{{{H^ \oplus } + \Delta }}D\xrightarrow{{HBr(1\,mole)}}E$
$(1)$ $PtCl_4·5NH_3$ $(2)$ $PtCl_4·4NH_3$
$(3)$ $PtCl4·3NH_3$ $(4)$ $PtCl4·2NH_3$