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STD 11 - 9. Hydricarbon — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 9. Hydricarbon4 Marks
MCQ
The reagent in Friedel Craft's reaction is
  • A
    Pyridine
  • ✓
    $RCOCl$
  • C
    $RCOOH$
  • D
    $HCl$
✓

Answer

Correct option: B.
$RCOCl$
b
(b) The reaction of an alkyl halide or aryl halide with benzene in the presence of a Lewis acid, generally $AlC{l_3}$ is known as Friedel Craft's reaction.

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