- Aconc. ${H_2}S{O_4}$
- BSodium alkoxide
- CDry silver oxide
- ✓Grignard reagent
$\underset{-MgBr(Cl)}{\mathop{\xrightarrow{C{{H}_{3}}MgBr}}}\,\underset{\begin{smallmatrix}
\text{Methoxyethane} \\
\,\,\text{(Higher}\,\text{ether)}
\end{smallmatrix}}{\mathop{C{{H}_{3}}OC{{H}_{2}}C{{H}_{3}}}}\,$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\frac{{ - d[A{B_5}]}}{{dt}} = K[A{B_5}]$ ; $\frac{{d[B]}}{{dt}} = {K_1}[A{B_5}]$
So the correct relation between $K$ and $K_1$ is
${CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br} \xrightarrow[\Delta]{\mathrm{KOH}_{(a k)}} \mathrm{A} \xrightarrow{\mathrm{HBr}} \mathrm{B} \xrightarrow[\mathrm{KOH}_{(a) i}]{\Delta} \mathrm{C}$
$\begin{matrix}
\underset{X}{\mathop{H}}{{O}_{2}}C-C{{H}_{2}}-CH-C{{O}_{2}}\underset{Z}{\mathop{H}}\, \\
\,\,\,\,\,\,\,\,\,\,\,| \\
\,\,\,\,\,\,\,\,\,\,\,\,\,+N{{H}_{3}} \\
\end{matrix}$
The isoelectric point for the amino acid is