MCQ
The reduction potential of hydrogen half-cell will be negative if :
- A$p(H_2) = 1\,atm$ and $[H^+] = 2.0\,M$
- B$p(H_2) = 1\,atm$ and $[H^+] = 1.0\,M$
- ✓$p(H_2) = 2\,atm$ and $[H^+] = 1.0\,M$
- D$p(H_2) = 2\,atm$ and $[H^+] = 2.0\,M$
$E=E^{\circ}-\frac{0.059}{1} \log \frac{P_{H_{2}}^{1 / 2}}{\left|H^{+1}\right|}$
Now if $P_{H_{2}}=2$ atm and $\left[H^{+}\right]=1 M$
then $E=0-\frac{0.059}{1} \log \frac{2^{1 / 2}}{1}=-2$
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Assertion $A:$ $3.1500\,g$ of hydrated oxalic acid dissolved in water to make $250.0\,mL$ solution will result in $0.1\,M$ oxalic acid solution.
Reason $R:$ Molar mass of hydrated oxalic acid is $126\,g\,mol ^{-1}$.
In the light of the above statements, chose the correct answer from the options given below:

