The relation between and parameters of current gains for a transi… - Vidyadip

MCQ

The relation between $\alpha$ and $\beta$ parameters of current gains for a transistors is given by

A
$\alpha = \frac{\beta }{{1 - \beta }}$
✓
$\alpha = \frac{\beta }{{1 + \beta }}$
C
$\alpha = \frac{{1 - \beta }}{\beta }$
D
$\alpha = \frac{{1 + \beta }}{\beta }$

✓

Answer

Correct option: B.

$\alpha = \frac{\beta }{{1 + \beta }}$

b
(b)${i_e} = {i_b} + {i_c}$$ \Rightarrow \frac{{{i_e}}}{{{i_c}}} = \frac{{{i_b}}}{{{i_c}}} + 1$$ \Rightarrow \frac{1}{\alpha } = \frac{1}{\beta } + 1$$ \Rightarrow \alpha = \frac{\beta }{{(1 + \beta )}}$.

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