MCQ
The relation between Faraday constant $(F)$, chemical equivalent $(E)$ and electrochemical equivalent $(Z)$ is
- A$F = EZ$
- B$F = \frac{Z}{E}$
- ✓$F = \frac{E}{Z}$
- D$F = \frac{E}{Z^2}$
where $E$ is chemical equivalent, $Z$ is electrochemical equivalent and $F$ is faraday constant.
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$A$. The stability of the hydrides decreases in the order $\mathrm{NH}_3>\mathrm{PH}_3>\mathrm{AsH}_3>\mathrm{SbH}_3>\mathrm{BiH}_3$
$B$. The reducing ability of the hydrides increases in the order $\mathrm{NH}_3<\mathrm{PH}_3<\mathrm{AsH}_3<\mathrm{SbH}_3<\mathrm{BiH}_3$
$C$. Among the hydrides, $\mathrm{NH}_3$ is strong reducing agent while $\mathrm{BiH}_3$ is mild reducing agent.
$D$. The basicity of the hydrides increases in the order $\mathrm{NH}_3<\mathrm{PH}_3<\mathrm{AsH}_3<\mathrm{SbH}_3<\mathrm{BiH}_3$Choose the most appropriate from the option given below: