MCQ
The relation between Faraday constant $(F),$ chemical equivalent $(E)$ and electrochemical equivalent $(Z)$ is
  • A
    $F=E Z$
  • B
    $\mathrm{F}=\frac{\mathrm{z}}{\mathrm{E}}$
  • $\mathrm{F}=\frac{\mathrm{E}}{\mathrm{z}}$
  • D
    $\mathrm{F}=\frac{\mathrm{E}}{\mathrm{Z}^2}$

Answer

Correct option: C.
$\mathrm{F}=\frac{\mathrm{E}}{\mathrm{z}}$
$\mathrm{F}=\frac{\mathrm{E}}{\mathrm{z}}$

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