MCQ
The relation between Faraday constant $(F),$ chemical equivalent $(E)$ and electrochemical equivalent $(Z)$ is
- A$F=E Z$
- B$\mathrm{F}=\frac{\mathrm{z}}{\mathrm{E}}$
- ✓$\mathrm{F}=\frac{\mathrm{E}}{\mathrm{z}}$
- D$\mathrm{F}=\frac{\mathrm{E}}{\mathrm{Z}^2}$
