Question
The relation between pressure exerted by an ideal gas ( $\left.P _{\text {ideal }}\right)$ and observed pressure ( $\left.P _{\text {real }}\right)$ is given by the equation, $p _{\text {ideal }}= p _{\text {real }}+\frac{ an ^2}{V^2}$
i. If pressure is taken in $Nm ^{-2}$, number of moles in mol and volume in $m ^3$, calculate the unit of ' a '.
ii. What will be the unit of 'a' when pressure is in atmosphere and volume in $dm ^3$ ?

Answer

Given that, $p _{\text {ideal }}= p _{\text {real }}+\frac{ an ^2}{V^2}$
i. $a =\frac{ pV ^2}{ n ^2}$ If units of $p = NM ^{-2}$,
units of $V=m^3$, units of $n=m o l$
then, units of $a =\frac{ Nm ^{-2}\left(m^3\right)^2}{(mol)^2}$
$=Nm^4 mol^{-2}$
ii. If units of $p=a t m$, units of $V=d m^3$, units of $n=m o l$ then, units of
$a=\frac{pV^2}{n^2}=\frac{atm\left(dm^3\right)^2}{(mol)^2}$
$=atm dm^6 mol^{-2}$

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