Question
The relation between the linear magnification $m,$ the object distance $u$ and the focal length $f$ is

Answer

(b) $m =  - \frac{v}{u}$ also $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

==> $\frac{u}{f} = \frac{u}{v} + 1$
==> $ - \frac{u}{v} = 1 - \frac{u}{f}$

$ \Rightarrow \frac{{ - v}}{u} = \frac{f}{{f - u}}$ so $m = \frac{f}{{f - u}}$.

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