MCQ
The relation between voltage sensitivity ($\sigma_v$) and current sensitivity ($\sigma_i$) of a moving coil galvanometer is (Resistance of Galvanometer = G)
  • $\frac{\sigma_{\mathrm{i}}}{\mathrm{G}}=\sigma_{\mathrm{v}}$
  • B
    $\frac{\sigma_{\mathrm{v}}}{\mathrm{G}}=\sigma_{\mathrm{i}}$
  • C
    $\frac{\mathrm{G}}{\sigma \mathrm{V}}=\sigma_{\mathrm{i}}$
  • D
    $\frac{\mathrm{G}}{\sigma_{\mathrm{i}}}=\sigma_{\mathrm{V}}$

Answer

Correct option: A.
$\frac{\sigma_{\mathrm{i}}}{\mathrm{G}}=\sigma_{\mathrm{v}}$
(a) $\frac{\sigma_{\mathrm{i}}}{\mathrm{G}}=\sigma_{\mathrm{v}}$

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