MCQ
The remainder on dividing $5^{99}$ by $11$ is
- ✓$9$
- B$18$
- C$27$
- D$36$
$=625\left[5^5\right]^{19}$
$=625[3125]^{19}$
$=625[3124+1]^{19}$
$=625[11 k \times 19+1]$
$=625 \times 11\,k \times 19+625$
$=11\,k _1+616+9$
$=11\left( k _2\right)+9$
Remainder $=9$
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