MCQ
The remainder when $(11)^{1011}+(1011)^{11}$ is divided by $9$ is
- A$1$
- B$4$
- C$6$
- ✓$8$
For $\operatorname{Re}\left(\frac{2^{1011}}{9}\right)$
$2^{1011}=(9-1)^{337}={ }^{337} C_{0} 9^{337}(-1)^{0}$
$+{ }^{337} C_{1} 9^{336}(-1)^{1}$
$+{ }^{337} C_{2} 9^{335}(-1)^{2}+\ldots \ldots$
$+{ }^{337} C_{337} 9^{0}(-1)^{337}$
so, remainder is $8$ and $\operatorname{Re}\left(\frac{3^{11}}{9}\right)=0$
So, remainder is $8$
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