MCQ
The remainder when $19^{200}+23^{200}$ is divided by $49$ , is $.........$.
- A$28$
- B$27$
- ✓$29$
- D$26$
$\Rightarrow 2\left[{ }^{100} C _0 21^{200}+200 C _2 21^{198} \cdot 2^2+\ldots . .+{ }^{200} C _{198} 21^2\right.$
$\left.2^{198}+2^{200}\right]$
$\Rightarrow 2\left[49 I _1+2^{200}\right]=49 I _1+2^{201}$
Now, $2^{201}=(8)^{67}=(1+7)^{67}=49 I _2+{ }^{67} C _0{ }^{67} C _1 \cdot 7=$ $49 I _2+470=49 I _2+49 \times 9+29$
$\therefore$ Remainder is $29$
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