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STD 11 - 7. binomial theoram — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 7. binomial theoram4 Marks
MCQ
The remainder, when $3^{2003}$ is divided by $28$, is
  • A
    $15$
  • B
    $5$
  • ✓
    $19$
  • D
    $9$
✓

Answer

Correct option: C.
$19$
c
$\frac{\left(3^{3}\right)^{667} \cdot 3^{2}}{28}=\frac{(28-1)^{667} \cdot 3^{2}}{28}=-9+28=19$

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