MCQ
The required charge for one equivalent weight of silver deposite on cathode is
- A$9.65 \times {10^7}\,C$
- ✓$9.65 \times {10^4}\,C$
- C$9.65 \times {10^3}\,C$
- D$9.65 \times {10^5}\,C$
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Reason : $NF_3$ ionizes to give $F^-$ ions in aqueous solution.
$\begin{array}{*{20}{c}}
{C{H_3} - C \equiv C - C{H_2} - \mathop C\limits_{\mathop {||}\limits_O } - Cl}
\end{array} \ \xrightarrow[{BaS{O_4}}]{{{H_2} - Pd}}$
