The resistance of $1\, A$ ammeter is $0.018\,\Omega $. To convert it into $10\, A$ ammeter, the shunt resistance required will be
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$S = \frac{{{i_g}G}}{{(i - {i_g})}}$$ = \frac{{1 \times 0.018}}{{10 - 1}} = \frac{{0.018}}{9} = 0.002\,\Omega $
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