MCQ
The restriction on n, k and p so that PY + WY will be define are:
  • k = 3, p = n
  • B
    k is arbitrary, p = 2
  • C
    p is arbitrary, k = 3
  • D
    k = 2, p = 3

Answer

Correct option: A.
k = 3, p = n
Given: $ \text{x}_{2\times n}, \text{y}_{3\times k},\text{ z}_{2 \times p}, \text{w}_{n \times 3}, \text{p}_{p\times k}$
Now, $\text{py + wy} = \text{p}_{p \times k}\times \text{y}_{3\times k}+\text{w}_{n\times3}\times\text{y}_{3 \times k}$
On comparing, k = 3 and p = n
Therefore, option (A) is correct.

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