The result after adding $3.8 \times 10^{-6}$ with $4.2 \times 10^{-5}$ with due regard to significant figures is
A$4.58 \times {10^{ - 5}}$
B$0.458 \times {10^{ -4 }}$
C$4.6 \times {10^{ - 5}}$
D$45.8 \times {10^{ - 6}}$
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C$4.6 \times {10^{ - 5}}$
c $3.8 \times 10^{-6}+42.0 \times 10^{-6}=45.8 \times 10^{-6}$
$=4.6 \times 10^{-5}$
Significant figure after decimal should be equal to one.
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