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STD 11 - 6.2. Equilibrium - II (icon Equilibrium) — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 6.2. Equilibrium - II (icon Equilibrium)4 Marks
MCQ
The salt that forms neutral solution in water is
  • A
    $N{H_4}Cl$
  • ✓
    $NaCl$
  • C
    $N{a_2}C{O_3}$
  • D
    ${K_3}B{O_3}$
✓

Answer

Correct option: B.
$NaCl$
(b) Because it is a salt of strong acid and strong base.

${H^ + }_{{\rm{(aq)}}} + C{l^ - }_{{\rm{(aq)}}} + N{a^ + }_{{\rm{(aq)}}} + O{H^ - }_{{\rm{(aq)}}} ⇌ {H_2}{O_{{\rm{(l)}}}} + N{a^ + }_{{\rm{(aq)}}} + C{l^ - }$

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