STD 11 - 3. Classification of elements and periodicity in properties — NEET STD 11 Science — Question

$Zn | ZnSO_4 \,(0.01\, M) | | CuSO_4\,(1.0\, M) | Cu$

When the concentration of $ZnSO_4$ is $1.0\,M$ and that of $CuSO_4$ is $0.01\,M$, the $emf$ changed to $E_2$ What is the relation between $E_1$ and $E_2$?

$(A)$ $\mathrm{O}$ $(B)$ $\mathrm{N}$ $(C)$ Be $(D)$ $\mathrm{F}$ $(E)$ $B$

Choose the correct answer from the options given below :