P-1 Arithmetic Progression — Maths STD 10 — Question

(B) is an A.P., Reason d = 4
First term a = – 10
Second term t₁ = – 6
Third term t₂ = – 2
Fourth term t₃ = 2
Common difference d = t₁ – a = – 6 – ( – 10) = – 6 + 10 = 4
Common difference d = t₂ – t₁ = – 2 – ( – 6) = – 2 + 6 = 4
Common difference d = t₃ – t₂ = 2 – ( – 2) = 2 + 2 = 4
Since, the common difference is same
∴ The given sequence is A.P. with common difference d = 4
Hence, correct answer is (B)