MCQ
The set $A = \{ x:x \in R,\,{x^2} = 16$ and $2x = 6\} $ equals
  • $\phi $
  • B
    $\{14, 3, 4\}$
  • C
    $\{3\}$
  • D
    $\{4\}$

Answer

Correct option: A.
$\phi $
a
(a) ${x^2} = 16$ ==> $x = \pm 4$

$2x = 6$ ==> $x = 3$

There is no value of $x$ which satisfies both the above equations. Thus, $A = \phi $.

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