MCQ
The shape of $2p$ orbital is
- ASpherical
- BEllipsoidal
- ✓Dumb-bell
- DPyramidal
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$_H^{Br} > \mathop C\limits_1 = \mathop C\limits_2 < _H^{Br}$ $\xrightarrow[{Catalyst}]{{{H_2}}}Br\mathop {C{H_2}}\limits_3 \mathop {C{H_2}}\limits_4 Br$
Assertion $A :$- Carbon forms two important oxides $- CO$ and $CO _2 . CO$ is neutral whereas $CO _2$ is acidic in nature.
Reason $R :$- $CO _2$ can combine with water in a limited way to form carbonic acid, while $CO$ is sparingly soluble in water.
In the light of the above statements, choose the most appropriate answer from the options given below :-