MCQ
The shape of a molecule which has $EB_5L_2$ moleculer formula
{$E\, =$ Central atom, $B\, =$ Terminal atom, $L\, =$ Lone pair}
- ASquare pyramidal
- ✓Pentagonal planar
- COctahedral
- DPentagonal pyramidal
✓
Answer
Correct option: B.
Pentagonal planar
b
$\operatorname{sp}^{3} \mathrm{d}^{2}(2 \mathrm{L} \mathrm{p}+5 \sigma)$
$\operatorname{sp}^{3} \mathrm{d}^{2}(2 \mathrm{L} \mathrm{p}+5 \sigma)$
$O R$
$sp^3d^3$ hybridisation with $2 \mathrm{LP}.$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In the compound $C{H_3}©OCl,$ which type of orbitals have been used by the circled carbon in bond formation
→In the periodic table, metallic character of the elements shows one of the following trend
The enolic form of acetone contains
The $IUPAC$ name of $C{H_2} = CH - C{H_2}Cl$ is
→An organic compound $^1C{H_3}{ - ^2}C{H_2}{ - ^3}C{H_2}{ - ^4}C{H_2}{ - ^5}C{H_2}{ - ^6}C{H_2}{ - ^7}C{H_3}$
→To make it chiral compound the attack should be on which carbon atom
According to $VSEPR$ theory
→Which of the following has largest ionic radius
The molecules represented by the above two structures are
The $IUPAC$ name of $\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_2} - CHO} \\
{\,\,\,\,\,\,\,\,\,\,|} \\
{OHC - C{H_2} - C{H_2} - CH - C{H_2} - CHO}
\end{array}$ is :
→{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_2} - CHO} \\
{\,\,\,\,\,\,\,\,\,\,|} \\
{OHC - C{H_2} - C{H_2} - CH - C{H_2} - CHO}
\end{array}$ is :
Among the following compounds which is planar in shape