MCQ
The shortest wavelength of hydrogen atom in Lyman series is $\lambda$. The longest wavelength in Balmer series of $He ^{+}$is
- A$\frac{5}{9 \lambda}$
- ✓$\frac{9 \lambda}{5}$
- C$\frac{36 \lambda}{5}$
- D$\frac{5 \lambda}{9}$
$\frac{1}{\lambda_{ He ^{+}}}= R _{ H } \times 2^2 \times\left(\frac{1}{4}-\frac{1}{9}\right)$
From $(1)$ and $(2)$ $\frac{\lambda_{ He ^{+}}}{\lambda}=\frac{9}{5}$
$\lambda_{ He ^{+}}=\lambda \times \frac{9}{5}$
$\lambda_{ He ^{+}}=\frac{9 \lambda}{5}$
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