Question
The sides of certain triangles are given below. Determine which of them are right triangles.
$a=7 cm, b=24 cm \text { and } c=25 cm$
$a=7 cm, b=24 cm \text { and } c=25 cm$
✓
Answer
We know that in a right angled triangle, the square of the largest side is equal to the sum of the squares of the smaller sides. Here, the larger side is c , which is 25 cm .
$c^2=625$
We have:
$a^2+b^2$
$=7^2+24^2$
$=49+576$
$=625=c^2$
Thus, the given triangle is a right triangle.
$c^2=625$
We have:
$a^2+b^2$
$=7^2+24^2$
$=49+576$
$=625=c^2$
Thus, the given triangle is a right triangle.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Find the HCF and LCM.32,16
Find the multiplicative inverse, or reciprocal of the following:
$\frac{-3}{-5}$
→$\frac{-3}{-5}$
Find the following product:
$\frac{3}{5}\text{m}^2\text{n}(\text{m}+5\text{n})$
→$\frac{3}{5}\text{m}^2\text{n}(\text{m}+5\text{n})$
Find:$\frac{12}{25}$ of a litre.
→In each of the following pairs of right triangles, the measures of some parts are indicated along side. State by the application of RHS congruence condition which are congruent. State each result in symbolic form.
Find x such that:
$\frac{13}{6}=\frac{-65}{\text{x}}$
→$\frac{13}{6}=\frac{-65}{\text{x}}$
Seperate positive and negative rational numbers from the following rational numbers:
$\frac{-5}{-7},\frac{12}{-5},\frac{7}{4},\frac{13}{-9},0,\frac{-18}{-7},\frac{-95}{116},\frac{-1}{-9}$
→$\frac{-5}{-7},\frac{12}{-5},\frac{7}{4},\frac{13}{-9},0,\frac{-18}{-7},\frac{-95}{116},\frac{-1}{-9}$
Find the following product:
$(x-6)(4 x+9)$
→$(x-6)(4 x+9)$
Find the LCM: $6,8,10$
→Find HCF of The Following : 25,40