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$(A) -CN$ $(B) -NO_2$ $(C) -NH_2$ $(D) -F$
$(ii)\, F_{(g)} + e^- \to F^-_{(g)}, \Delta H_2$
$(iii)\, Cl_{(g)} + e^- \to Cl_{(g)}, \Delta H_3$
$(iv)\, O_{(g)}^- + e^- \to O_{(g)}^{2-} , \Delta H_4$
That according to given information the incorrect statement is
$2KCl{O_4}(s) \rightleftharpoons 2KCl(s) + 3{O_2}(g)$
If $\Delta {H^o} = 25\,kcal/mol$ and $\Delta {S^o} = 50\,cal/K$, at what temperature equilibrium will be established in the container. (Ignore variation of $\Delta {H^o}$ and $\Delta {S^o}$ with temperature.)......$K$
| Compound | Weight $\%$ of $P$ | Weight $\%$ of $Q$ |
| $1$ | $50$ | $50$ |
| $2$ | $44.4$ | $55.6$ |
| $3$ | $40$ | $60$ |
$(A)$ If empirical formula of compound $3$ is $P_3 Q_4$, then the empirical formula of compound $2$ is $P_3 Q_5$.
$(B)$ If empirical formula of compound $3$ is $P _3 Q _2$ and atomic weight of element $P$ is $20$ , then the atomic weight of $Q$ is $45$ .
$(C)$ If empirical formula of compound $2$ is $PQ$, then the empirical formula of the compound $1$ is $P _5 Q _4$.
$(D)$ If atomic weight of $P$ and $Q$ are $70$ and $35$ , respectively, then the empirical formula of compound $1$ is $P _2 Q$.