$\text{I}_0$
$\frac{\text{I}_0}{4}$
$\frac{\text{I}_0}{2}$
$4\text{I}_0$
Explanation:
Total intensity coming from the source is I0 which is present at the central maxima. In case of two slits, the intensity is getting distributed between the two slits and for a single slit, the amplitude of light coming from the slit is reduced to half which leads to $\frac{1}{4}\text{th}$ of intensity.
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$\overrightarrow{\text{F}}\times\overrightarrow{\text{a}}$
$\overrightarrow{\text{v}}\times\overrightarrow{\text{r}}$
$\overrightarrow{\text{a}}\times\overrightarrow{\text{r}}$
$\overrightarrow{\text{F}}\times\overrightarrow{\text{r}}$
$\text{E}_0\text{k}=\text{B}_0\omega$
$\text{E}_0\text{B}_0=\omega\text{k}$
$\text{E}_0\omega=\text{B}_0\text{k}$
What is the net force on a Cl– placed at the centre of the bcc structure of CsCl
|
(a) Zero |
(b) |
(c) |
(d) Data is incomplete |
The energy band gap of Si is
|
(a) 0.70 eV |
(b) 1.1 eV |
|
(c) Between 0.70 eV to 1.1 eV |
(d) 5 eV |
The capacity of a spherical conductor in MKS system is
|
(a) |
(b) |
(c) |
(d) |
