- A$PCl_5$
- B$PCl_4 ^+ \,Cl^-$
- C$PCl_6^-$
- ✓$PCl_4^+\, PCl_6^-$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\begin{matrix}
C{{H}_{3}}CHCOOH\xrightarrow{\Delta }\,Product \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\end{matrix}$
$Ni ( s )+2 Ag ^{+}(0.001 M ) \rightarrow Ni ^{2+}(0.001 M )+2 Ag ( s )$
$($ Given that $E _{\text {cell }}^{\circ}=10.5 \,V , \frac{2.303 RT }{ F }=0.059$ at $298\, K )$

$Mg\left( s \right) + \mathop {2A{g^ + }}\limits_{(0.0001\,M)} \to \mathop {M{g^{ + 2}}}\limits_{\left( {0.100\,M} \right)} + 2Ag\left( s \right)$
If $E_{cell}^o = 3.17\,V$
$1$. $NH_3 + NH_4Cl$
$2$. $HCl + NaCl$
$3$. $NH_3 + HCl$ in $2 : 1$ $mole$ ratio
Select the correct answer using the code given below