The solubility of ammonium chloride in water at various temperatures is given below:
What mass of ammonium chloride whould be needed to make a saturated solution of ammonium chloride in fifty grams of water at $40^\circ\ C$?
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Temperature:
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$10^\circ\ C$
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$20^\circ\ C$
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$40^\circ\ C$
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$60^\circ\ C$
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$80^\circ\ C$
|
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Solubility:
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$24g$
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$37g$
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$41g$
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$55g$
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$66g$
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Given that, Solubility at $40^\circ C = 41\ gm$
solubility = Solid dissolved in $100$ grams of water in a solution So,
mass of ammonium chloride, required to make a saturated solution of ammonium chloride, in $50\ gm$ of water at $40^\circ\text{C}=\frac{41}{2}\text{g}=20.5\text{gm}$
solubility = Solid dissolved in $100$ grams of water in a solution So,
mass of ammonium chloride, required to make a saturated solution of ammonium chloride, in $50\ gm$ of water at $40^\circ\text{C}=\frac{41}{2}\text{g}=20.5\text{gm}$
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