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6.2. Equilibrium - II (icon Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.2. Equilibrium - II (icon Equilibrium)1 Mark
MCQ
The solubility product of $A{g_2}Cr{O_4}$ is $32 \times {10^{ - 12}}$. What is the concentration of $CrO_4^ - $ ions in that solution
  • ✓
    $2 \times {10^{ - 4}}\,m/s$
  • B
    $16 \times {10^{ - 4}}\,m/s$
  • C
    $8 \times {10^{ - 4}}\,m/s$
  • D
    $8 \times {10^{ - 8}}\,m/s$
✓

Answer

Correct option: A.
$2 \times {10^{ - 4}}\,m/s$
(a) $\mathop {AgCr{O_4}}\limits_S \to \mathop {2A{g^ + }}\limits_{2S} + \mathop {Cr{O_4}^{ - \,\, - }}\limits_S $

${K_{sp}} = {(2S)^2}S = 4{S^3}$

$S = {\left( {\frac{{{K_{sp}}}}{4}} \right)^{\frac{1}{3}}}$$ = {\left( {\frac{{32 \times {{10}^{ - 12}}}}{4}} \right)^{\frac{1}{3}}}$ $ = 2 \times {10^{ - 4}}$ $M$.

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