The solubility product of Hg_2I_2 is equal to - Vidyadip

MCQ

The solubility product of $Hg_2I_2$ is equal to

A
$\left[ {Hg_2^{ + 2}} \right]\left[ {{I^ - }} \right]$
B
$\left[ {H{g^{ + 2}}} \right]\left[ {{I^ - }} \right]$
✓
$\left[ {H{g_2}^{ + 2}} \right]{\left[ {{I^ - }} \right]^2}$
D
${\left[ {H{g^{ + 2}}} \right]^2}{\left[ {{I^ - }} \right]^2}$

✓

Answer

Correct option: C.

$\left[ {H{g_2}^{ + 2}} \right]{\left[ {{I^ - }} \right]^2}$

c
For $Hg _2 I _2$,

$Hg _2 I _2 \rightleftharpoons Hg _2{ }^{2+}+2 I ^{-}$

Let the solubility product be $K _{\text {sp }}$.

$K _{ sp }=\left[ Hg _2{ }^{2+}\right]\left[ I ^{-}\right]^2$

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