MCQ
The solution from the following with highest depression in freezing point/lowest freezing point is
  • 180 g of acetic acid dissolved in water
  • B
    180 g of acetic acid dissolved in benzene
  • C
    180 g of benzoic acid dissolved in benzene
  • D
    180 g of glucose dissolved in water

Answer

Correct option: A.
180 g of acetic acid dissolved in water
(A)
$\Delta T_f$ is maximum when $i \times m$ is maximum.
1) $m _1=\frac{180}{60}=3, i =1+\alpha$Hence$
\Delta T_{f}=(1+\alpha) \cdot k_{f}=3 \times 1.86=5.58^{\circ} C(\alpha<<1)
$
2) $m _2=\frac{180}{60}=3, i =0.5, \Delta T_{ f }=\frac{3}{2} \times k _{ f }{ }^{\prime}=7.68^{\circ} C$
3) $m _3=\frac{180}{122}=1.48, i =0.5, \Delta T_{ f }=\frac{1.48}{2} \times k _{ f }{ }^{\prime}=3.8^{\circ} C$
4) $m _4=\frac{180}{180}=1, i =1, \Delta T_{ f }=1 \cdot k _{ f }{ }^{\prime}=1.86^{\circ} C$
As per NCERT, $k _{ f }{ }^{\prime}\left( H _2 O \right)=1.86 k \cdot kg mol ^{-1}$
$
k_{f}{ }^{\prime}(\text { Benzene })=5.12 k \cdot kg mol^{-1}
$

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