MCQ
The solution of $\Big|\frac{2}{(\text{x} – 4)}\Big|>1$ where $\text{x}\neq4$ is:
  • A
    $(2, 6)$
  • $(2, 4)\cup(4, 6)$
  • C
    $(2, 4)\cup(4,\infty)$
  • D
    $(-\infty, 4)\cup(4, 6)$

Answer

Correct option: B.
$(2, 4)\cup(4, 6)$
Given,$\Big|\frac{2}{(\text{x} – 4)}\Big|>1$
$\Rightarrow2 > |\text{x} – 4|$
$\Rightarrow |\text{x} – 4|<2$
$\Rightarrow-2<\text{x}-4<2$
$\Rightarrow-2+4 < \text{x} < 2+4$
$\Rightarrow2<\text{x}<6$
$\Rightarrow\text{x}\in(2, 6),$
where $\text{x}\neq4$
$\Rightarrow\text{x}\in(2, 4)\cup(4, 6)$

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