MCQ
The solution of differential equation $dy - \sin x\sin ydx = 0$ is
- ✓${e^{\cos x}}\tan \frac{y}{2} = c$
- B${e^{\cos x}}\tan y = c$
- C$\cos x\tan y = c$
- D$\cos x\sin y = c$
==> $\tan \frac{y}{2} = {e^{ - \cos x + c}}$ ==> ${e^{\cos x}}\tan \frac{y}{2} = {e^C} = c$.
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