MCQ
The solution of $\frac{{dy}}{{dx}} = {e^x}(\sin x + \cos x)$ is
- A$y = {e^x}(\sin x - \cos x) + c$
- B$y = {e^x}(\cos x - \sin x) + c$
- ✓$y = {e^x}\sin x + c$
- D$y = {e^x}\cos x + c$
✓
Answer
Correct option: C.
$y = {e^x}\sin x + c$
c
(c) Given equation $\frac{{dy}}{{dx}} = {e^x}(\sin x + \cos x)$
(c) Given equation $\frac{{dy}}{{dx}} = {e^x}(\sin x + \cos x)$
==> $dy = {e^x}(\sin x + \cos x)dx$
On integrating, we get $y = {e^x}\sin x + c$.
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