MCQ
The solution of $\frac{{dy}}{{dx}} = \left( {\frac{{ax + b}}{{cy + d}}} \right)$ represents a parabola if
  • A
    $a = 0, c = 0$
  • B
    $a = 1, c = 2$
  • $a = 0,c \ne 0$
  • D
    $a = 1, c = 1$

Answer

Correct option: C.
$a = 0,c \ne 0$
c
$(c y+d) d y=(a x+b) d x$

$\frac{\mathrm{cy}^{2}}{2}+\mathrm{dy}=\frac{\mathrm{ax}^{2}}{2}+\mathrm{bx}+\mathrm{K}$ ($K$ being the constant of integration)

The equation represents a parabola

If $\mathrm{c}=0, \mathrm{a} \neq 0$ or $\mathrm{a}=0, \mathrm{c} \neq 0$

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