MCQ
The solution of ${e^{2x - 3y}}dx + {e^{2y - 3x}}dy = 0$ is
- ✓${e^{5x}} + {e^{5y}} = c$
- B${e^{5x}} - {e^{5y}} = c$
- C${e^{5x + 5y}} = c$
- DNone of these
Multiply the equation by ${e^{3x + 3y}}$ ==> ${e^{5x}}dx + {e^{5y}}dy = 0$
On integrating, we get ${e^{5x}} + {e^{5y}} = 5c' = c$.
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$a x+2 y=\lambda$
$3 x-2 y=\mu$Which of the following statement($s$) is(are) correct?
($A$) If $a=-3$, then the system has infinitely many solutions for all values of $\lambda$ and $\mu$
($B$) If $a \neq-3$, then the system has a unique solution for all values of $\lambda$ and $\mu$
($C$) If $\lambda+\mu=0$, then the system has infinitely many solutions for $a=-3$
($D$) If $\lambda+\mu \neq 0$, then the system has no solution for $a=-3$