MCQ
The solution of $\log \,\left( {\frac{{dy}}{{dx}}} \right) = ax + by$ is
- A$\frac{{{e^{by}}}}{b} = \frac{{{e^{ax}}}}{a} + c$
- ✓$\frac{{{e^{ - by}}}}{{ - b}} = \frac{{{e^{ax}}}}{a} + c$
- C$\frac{{{e^{ - by}}}}{a} = \frac{{{e^{ax}}}}{b} + c$
- DNone of these