MCQ
The solution of $\frac{\text{dy}}{\text{dx}}+\frac{\text{y}}{\text{x}}=\frac{1}{\sqrt{1+\text{x}^2}}$ is:
- A$\text{y}=\frac{1+\text{x}^2}{\text{x}}+\frac{\text{c}}{\text{x}}$
- ✓$\text{y}=\frac{\sqrt{1+\text{x}^2}}{\text{x}}+\frac{\text{c}}{\text{x}}$
- C$\text{y}=\frac{\text{x}}{\sqrt{1+\text{x}^2}}+\text{cx}$
- DNone of these
