MCQ
The solution of the differential equation $\frac{{dy}}{{dx}} = {x^2} + \sin 3x$ is
- A$y = \frac{{{x^3}}}{3} + \frac{{\cos 3x}}{3} + c$
- ✓$y = \frac{{{x^3}}}{3} - \frac{{\cos 3x}}{3} + c$
- C$y = \frac{{{x^3}}}{3} + \sin 3x + c$
- DNone of these
On integrating, $y = \frac{{{x^3}}}{3} - \frac{{\cos 3x}}{3} + c$.
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Statement $-1 :$ If $A \ne I,A \ne - I$ then $\det \left( A \right) = - 1$
Statement $-2 :$ If $A \ne I,A \ne - I$ then ${\rm{tr}}\left( A \right) \ne 0$
$(A)$ $f (2)<1-\log _{ e } 2$ $(B)$ $f (2)>1-\log _{ e } 2$ $(C)$ $g(1)>1-\log _e 2$ $(D)$ $g(1)<1-\log _e 2$