MCQ
The solution of the differential equation $\frac{{dy}}{{dx}} = {x^2} + \sin 3x$ is
  • A
    $y = \frac{{{x^3}}}{3} + \frac{{\cos 3x}}{3} + c$
  • $y = \frac{{{x^3}}}{3} - \frac{{\cos 3x}}{3} + c$
  • C
    $y = \frac{{{x^3}}}{3} + \sin 3x + c$
  • D
    None of these

Answer

Correct option: B.
$y = \frac{{{x^3}}}{3} - \frac{{\cos 3x}}{3} + c$
b
(b) $\frac{{dy}}{{dx}} = {x^2} + \sin 3x$.

On integrating, $y = \frac{{{x^3}}}{3} - \frac{{\cos 3x}}{3} + c$.

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