MCQ
The solution of the equation $\frac{2^3}{\log3\text{x}}=\frac{1}{64}$ is?
- A$3$
- B$\frac{1}{3}$
- ✓$\frac{1}{\sqrt{(3)}}$
- D$\text{None of these}$
$\frac{3}{\log_3\text{x}}=-6$
$\therefore64=2^6$
$\therefore\log_3\text{x}=-\frac{1}{2}$ or $\text{x}=3^{-\frac{1}{2}}=\frac{1}{\sqrt3}$
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