MCQ
The solution of the equation $2{x^2} + 3x - 9 \le 0$ is given by
  • A
    $\frac{3}{2} \le x \le 3$
  • $ - 3 \le x \le \frac{3}{2}$
  • C
    $ - 3 \le x \le 3$
  • D
    $\frac{3}{2} \le x \le 2$

Answer

Correct option: B.
$ - 3 \le x \le \frac{3}{2}$
b
(b) $2{x^2} + 3x - 9 \le 0$

==> $2{x^2} + 6x - 3x - 9 \le 0$

==> $2x(x + 3) - 3(x + 3) \le 0$

==> $(2x - 3)(x + 3) \le 0$

==> $ - 3 \le x \le 3/2$.

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