MCQ
The solution of the equation $2{x^2} + 3x - 9 \le 0$ is given by
- A$\frac{3}{2} \le x \le 3$
- ✓$ - 3 \le x \le \frac{3}{2}$
- C$ - 3 \le x \le 3$
- D$\frac{3}{2} \le x \le 2$
==> $2{x^2} + 6x - 3x - 9 \le 0$
==> $2x(x + 3) - 3(x + 3) \le 0$
==> $(2x - 3)(x + 3) \le 0$
==> $ - 3 \le x \le 3/2$.
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