The solution of the equation (2y - 1) , ,dx - (2x + 3) ,dy = 0 is - Vidyadip

MCQ

The solution of the equation $(2y - 1)\,\,dx - (2x + 3)\,dy = 0$ is

A
$\frac{{2x - 1}}{{2y + 3}} = c$
B
$\frac{{2y + 1}}{{2x - 3}} = c$
✓
$\frac{{2x + 3}}{{2y - 1}} = c$
D
$\frac{{2x - 1}}{{2y - 1}} = c$

✓

Answer

Correct option: C.

$\frac{{2x + 3}}{{2y - 1}} = c$

c
(c) $\frac{{dy}}{{2y - 1}} = \frac{{dx}}{{2x + 3}}$

==> $\frac{1}{2}\log (2y - 1) = \frac{1}{2}\log (2x + 3) + \log c$ ==> $\frac{{2x + 3}}{{2y - 1}} = c$.

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