MCQ
The solution set for $(x+3)+4>-2 x+5$ :
  • A
    $(-\infty, 2)$
  • B
    $\left(\frac{-2}{3}, \infty\right)$
  • C
    $(-\infty,-2)$
  • D
    $(2, \infty)$

Answer

(b) $\left(\frac{-2}{3}, \infty\right)$
Explanation: $(x+3)+4>-2 x+5$
$\begin{array}{l}\Rightarrow x+7>-2 x+5 \\
\Rightarrow x+7+2 x>-2 x+5+2 x \\
\Rightarrow 3 x+7>5 \\
\Rightarrow 3 x+7-7>5-7 \\
\Rightarrow 3 x>-2 \\
\Rightarrow x>\frac{-2}{3} \\
\Rightarrow x \in\left(\frac{-2}{3}, \infty\right)\end{array}$

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