MCQ
The solution set of the equation ${x^{{{\log }_x}{{(1 - x)}^2}}} = 9$ is
- ✓$\{-2, 4\}$
- B$\{4\}$
- C$\{0, -2, 4\}$
- DNone of these
==>${\log _x}(9) = {\log _x}{(1 - x)^2}({a^x} = N\,\,\, $
$\Rightarrow {\log _a}N = x)$
==> $9 = {(1 - x)^2}\,\,\,$
$ \Rightarrow 1 + {x^2} - 2x - 9 = 0$
==> ${x^2} - 2x - 8 = 0$
==> $(x + 2)(x - 4) = 0$ ==> $x = - 2\,,4$.
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