MCQ
The solution set of the inequation 2x + y > 5 is:
- Ahalf plane that contains the origin
- Bopen half plane not containing the origin
- Cwhole xy-plane except the points lying on the line 2x + y = 5
- Dnone of these
Solution:
On putting x = 0, y = 0 in the given inequality, we get 0 > 5, which is absurd.
Therefore, the solution set of the given inequality does not include the origin.
Thus, the solution set of the given inequality consists of the open half plane not containing the origin.
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General solution of $\frac{\text{dy}}{\text{dx}}+\text{y}\tan\text{x}=\sec\text{x}$ is:
$\text{y}\sec\text{x}=\tan\text{x}+\text{c}$
$\text{y}\tan\text{x}=\sec\text{x}+\text{c}$
$\tan\text{x}=\sec\text{x}+\text{c}$
$\text{x}\sec\text{x}=\tan\text{y}+\text{c}$
$\text{f(x)}=1,\ \text{f(y)}\neq1,\ \text{f(z)}\neq2.$
The value of f-1(1)is: