The space inside a straight current carrying solenoid is filled with a magnetic material having magnetic susceptibility equal to $1.2 \times 10^{-5}$. What is fractional increase in the magnetic field inside solenoid with respect to air as medium inside the solenoid?
A$1.2 \times 10^{-5}$
B$1.2 \times 10^{-3}$
C$1.8 \times 10^{-3}$
D$2.4 \times 10^{-5}$
JEE MAIN 2022, Medium
Download our app for free and get started
A$1.2 \times 10^{-5}$
a $\chi=1.2 \times 10^{-5}$
$\mu_{ r }=1+\chi=1+1.2 \times 10^{-5}$
Fractional Change
$=\frac{\Delta B }{ B }=\frac{\mu_{0} \mu_{ I } ni -\mu_{0} ni }{\mu_{0} ni }=\left(\mu_{ r }-1\right)$
$=1.2 \times 10^{-5}$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A galvanometer of resistance $20 \,\Omega$ is to be converted into an ammeter of range $1\, A$. If a current of $1\, mA$ produces full scale deflection, the shunt required for the purpose is ................ $\Omega $
Two coaxial solenoids $1$ and $2$ of the same length are set so that one is inside the other. The number of turns per unit length are ${n_1}$ and ${n_2}$. The currents ${i_1}$ and ${i_2}$ are flowing in opposite directions. The magnetic field inside the inner coil is zero. This is possible when
Two long conductors are arranged as shown above to form overlapping cylinders, each of raidus $r$, whose centers are separated by a distance $d$. Current of density $J$ flows into the plane of the page along the shaded part of one conductor and an equal current flows out of the plane of the page along the shaded portion of the other, as shown. What are the magnitude and direction of the magnetic field at point $A?$
A negative test charge is moving near a long straight wire carrying a current. The force acting on the test charge is parallel to the direction of the current. The motion of the charge is
The circuit in figure consists of wires at the top and bottom and identical springs as the left and right sides. The wire at the bottom has a mass of $10\, g$ and is $5\, cm$ long. The wire is hanging as shown in the figure. The springs stretch $0.5\, cm$ under the weight of the wire and the circuit has a total resistance of $12\, \Omega $. When the lower wire is subjected to a static magnetic field, the springs, stretch an additional $0.3\, cm$. The magnetic field is
In the circuit diagrams $(A, B, C$ and $D$) shown below, $R$ is a high resistance and $S$ is a resistance of the order of galvanometer resistance $G$. The correct circuit, corresponding to the half deflection method for finding the resistance and figure of merit of the galvanometer, is the circuit labelled as
A straight wire carrying a current ${i_1}\,amp$ runs along the axis of a circular current ${i_2}\,amp$. Then the force of interaction between the two current carrying conductors is
A beam of neutrons performs circular motion of radius, $r=1 \,m$. Under the influence of an inhomogeneous magnetic field with inhomogeneity extending over $\Delta r=0.01 \,m$. The speed of the neutrons is $54 \,m / s$. The mass and magnetic moment of the neutrons respectively are $1.67 \times 10^{-27} \,kg$ and $9.67 \times 10^{-27} \,J / T$. The average variation of the magnetic field over $\Delta r$ is approximately ....... $T$